2(x-5)^2+8=20

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Solution for 2(x-5)^2+8=20 equation: 



2(x-5)^2+8=20

We move all terms to the left:

2(x-5)^2+8-(20)=0

We add all the numbers together, and all the variables

2(x-5)^2-12=0

We move all terms containing x to the left, all other terms to the right

2(x-5)^2=12

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